# Calculate the volume of carbon dioxide required to react with 0.05 mol of calcium hydroxide.

August 24, 2021 | education

| 1. Let us write the equation according to the problem statement:

X l. -? Y = 0.05 mol;

CO2 + Ca (OH) 2 = CaCO3 + H2O – ion exchange reaction, obtained calcium carbonate in the sediment;

2. We make calculations by the formulas:

M (CO2) = 44 g / mol;

M Ca (OH) 2 = 74 g / mol.

3. The amount of starting materials:

Y Ca (OH) 2 = 0.05 mol (equation data);

Y (CO2) = 0.05 mol since the amount of these substances is equal to 1 mol according to the equation.

4. Find the volume of the original substance:

V (CO2) = 0.05 * 22.4 = 1.12 liters.

Answer: to carry out the process, carbon monoxide with a volume of 1.12 liters is required.

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